Question #25959

1 Answer
Dec 6, 2016

Answer:

2.34 gram

Explanation:

Balanced equation:
#Pb(NO3)2(aq) + 2NaCl(aq) -> PbCl2(s) + 2NaNO3(aq)#

And as for the "the percentage formed weighed 5.56g" part of the original question...

I'm going to assume that you mean the precipitate, #PbCl2(s)# weighs 5.56 gram.

I can see that you would like to know the mass of #NaCl#.
Let's use the molar ratios from the balanced chemical equation to calculate the mass of #NaCl#

Consider below:
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