# Question #25959

Dec 6, 2016

2.34 gram

#### Explanation:

Balanced equation:
$P b \left(N O 3\right) 2 \left(a q\right) + 2 N a C l \left(a q\right) \to P b C l 2 \left(s\right) + 2 N a N O 3 \left(a q\right)$

And as for the "the percentage formed weighed 5.56g" part of the original question...

I'm going to assume that you mean the precipitate, $P b C l 2 \left(s\right)$ weighs 5.56 gram.

I can see that you would like to know the mass of $N a C l$.
Let's use the molar ratios from the balanced chemical equation to calculate the mass of $N a C l$

Consider below: