# What is the number of electrons in a 1.5*mol quantity of dioxygen gas?

In $1.5 \cdot m o l$ of $\text{dioxygen gas}$?
The oxygen $\text{atom}$ has $8$ electrons. And thus if we have $1.5 \cdot m o l$ ${O}_{2}$ molecules, there are ${N}_{A} \times 1.5 \times 2 \times 8 = 24 \times {N}_{A} \text{ electrons}$, where ${N}_{A} = \text{Avogadro's Number} \equiv 6.022 \times {10}^{23} \cdot m o {l}^{-} 1$.