Question

Question #8f0ee

Answer 1

`u_H = 8.8 m.s⁻¹`

Explanation:

The discus is thrown at 51º to the ground. We only need to use trigonometry to solve this problem. The diagram below shows the launch vector and that vector broken into its vertical and horizontal components.

In order to solve the question we use:
`u_H = u cos θ = 14 × cos 51 = 8.8 m.s⁻¹` (2 s.f.)