# Question #db6bd

Dec 9, 2016

See explanation.

#### Explanation:

It is not possible to calculate scaled tank's dimensions without the original dimensions.

Only thing I can say about the dimensions is:

1. The dimensions are 12 times smaller than the original.
2. The volume of the scaled tank is ${12}^{3} = 1728$ times smaller.

So the scaled volume will be: ${V}_{s} = \frac{1}{1728} \times 120 = \frac{10}{144} = \frac{5}{72} l$