Question #8b2ee

1 Answer
Dec 10, 2016

Answer:

The mass of one atom of iron is #(9.2741105xx10^-23)#.

Explanation:

The formula we are using is #m=M/n#. Where...
=> #m# is the mass in grams.
=> #M# is the molar mass in #g/(mol)#.
=> #n_"A"# is Avogadro's number - #6.02xx10^23#.

#m=M/n_"A"#

#=55.85/(6.02xx10^23)#

#=(9.2741105xx10^-23)#

The mass of one atom of iron is #(9.2741105xx10^-23)#.

Hope this helps :)