Question

Question #c09ab

Answer 1

The answer is `=(n-1)/(2n)`

Explanation:

Let's start by simplifying inside each bracket

`(1-1/n)(1-1/(n+1))(1-1/(n+2))..(1-1/(2n-1))(1-1/(2n))..`

`=((n-1)/canceln)(canceln/cancel(n+1))(cancel(n+1)/cancel(n+2))...(cancel(2n)/cancel(2n-1))(cancel(2n-1)/(2n))`

`=(n-1)/(2n)`