# How do you solve #t^3-13t-12=0# ?

##### 1 Answer

Dec 22, 2016

#### Answer:

The solutions are

#### Explanation:

Given:

#f(t) = t^3-13t-12#

Notice that

We find:

#f(-1) = -1+13-12 = 0#

So

#t^3-13t-12 = (t+1)(t^2-t-12)#

To factor

The pair

#t^2-t-12 = (t-4)(t+3)#

So the other two zeros are:

#t = 4" "# and#" "t = -3#