# How much energy does the oxidation of 6.03 L of nitrogen absorb?

##### 1 Answer

#### Answer:

The reaction absorbs 2.47 kJ.

#### Explanation:

You don’t say what the oxidation product is, so I shall assume that it is dinitrogen tetroxide.

Then the reaction is

The formula for the amount of heat

#color(blue)(barul|stackrel(" ")(q = nΔ_text(f)H)|)#

where

**Step 1. Calculate the number of moles of #"N"_2#**

We know that the volume of 1 mol of nitrogen at 1 atm and 273 K (the old definition of **STP**) is 22.4 L.

∴

**Step 2. Calculate the amount of heat absorbed**