Question #788ea

1 Answer
P dilip_k
Dec 19, 2016

#CuSO_4# ionises as follows

#CuSO_4rightleftharpoonsCu^"2+"+SO_4^"2-"#

So 1 mol #CuSO_4# pruduces 1mol #Cu^"2+"# ions.
#Zn# reduces #Cu^"2+"# ion as follows

#Cu^"2+"+Zn-> Cu + Zn^"2+"#

This equation tells that #1mol" "Cu^"2+"# requires #1mol" " Zn# for its reduction.

Now #5L" "1xx10^-3M CuSO_4# contains #5xx10^-3# mol #CuSO_4 # which produces # 5xx10^-3# mol #Cu^2+# ions and these ions require #5xx10^-3 mol" " Zn# atoms.

Mass of this Zn is

#=5xx10^-3" mol"xx "molar mass of Zn"#

#=5xx10^-3" mol"xx 65.38g/"mol"#

#=0.3269g#

Related questions
See all questions in Electrolysis
Impact of this question
1582 views around the world
You can reuse this answer
Creative Commons License