Question

Question #788ea

Answer 1

`CuSO_4` ionises as follows

`CuSO_4rightleftharpoonsCu^"2+"+SO_4^"2-"`

So 1 mol `CuSO_4` pruduces 1mol `Cu^"2+"` ions.
`Zn` reduces `Cu^"2+"` ion as follows

`Cu^"2+"+Zn-> Cu + Zn^"2+"`

This equation tells that `1mol" "Cu^"2+"` requires `1mol" " Zn` for its reduction.

Now `5L" "1xx10^-3M CuSO_4` contains `5xx10^-3` mol `CuSO_4` which produces `5xx10^-3` mol `Cu^2+` ions and these ions require `5xx10^-3 mol" " Zn` atoms.

Mass of this Zn is

`=5xx10^-3" mol"xx "molar mass of Zn"`

`=5xx10^-3" mol"xx 65.38g/"mol"`

`=0.3269g`