Question #bcd5b

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Question #bcd5b

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Answer 1 · 2018-02-04T00:59:04

$K_{2} O$ $K_2O$

Explanation:

Potassium has a tendency to lose $1$ $1$ electron to become $K^{+}$ $K^+$ , while oxygen wants to gain $2 e^{-}$ $2e^-$ to complete its octet, so it becomes $O^{2 -}$ $O^(2-)$ .

Combining,

$K^{+}$ $K^+$ $O^{2 -}$ $O^(2-)$

We have to criss cross, so the $2$ $2$ goes to potassium, while $1$ $1$ goes to oxygen, so our final formula is:

$K_{2} O$ $K_2O$

This is a compound called potassium oxide.

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