Question #bcd5b

Feb 4, 2018

${K}_{2} O$

Explanation:

Potassium has a tendency to lose $1$ electron to become ${K}^{+}$, while oxygen wants to gain $2 {e}^{-}$ to complete its octet, so it becomes ${O}^{2 -}$.

Combining,

${K}^{+}$${O}^{2 -}$

We have to criss cross, so the $2$ goes to potassium, while $1$ goes to oxygen, so our final formula is:

${K}_{2} O$

This is a compound called potassium oxide.