# Question #34d69

Dec 26, 2016

$\left(2 , \pm 5\right) \mathmr{and} \left(- 3 , \pm 2 \sqrt{5}\right)$

#### Explanation:

The graph is made using $\left({x}^{2} + {y}^{2} - 29\right) \left({y}^{2} - x - 23\right) = 0$

The circle and the parabola intersect at the four points

$\left(2 , \pm 5\right) \mathmr{and} \left(- 3 , \pm 2 \sqrt{5}\right)$

These values are obtained by solving the two simultaneous

equations, for common ( x, y )..

graph{(x^2+y^2-29)(y^2-x-23)=0 [-40, 40, -20, 20]}