Question #7ea2e

1 Answer
Dec 22, 2016

The interacting ratio of number of moles of #NH_3 and O_2# as per above equation is #4:5=4/5:1=0.8:1#

So if the 1 mole of each reactant here is made to react, #O_2# will be fully consumed reacting with #0.8# mole #NH_3# and as a result #0.2# mole of #NH_3# only will remain as residue.