Question #1cea0

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Answer 1 · 2016-12-23T17:54:24

The answer is #=1 # sq units

Area of circle #=pir^2#

#:. pir^2=pi#

radius #r=1#

#AC=sqrt(1+1)=sqrt2#

Area of sector ACB #=1/2*r^2*theta#

#theta =AhatCB=90º=pi/2 rad#

Area of sector ACB #=1/2(sqrt2)^2*pi/2=pi/2#

Area of #Delta ABC=1/2*2*1=1#

Area of segment #=pi/2-1#

Half area of circle (diameter AB) #=pi/2#

Area of shaded part = Half area of circle -area of segment

#=pi/2-(pi/2-1)=pi/2-pi/2+1=1#