How many molecules are present in a #27*g# mass of #OF_2(g)#?

1 Answer
anor277
Dec 30, 2016

#"Number of molecules"# #-=# #"Number of moles"xxN_A#......

Explanation:

Where #N_A="Avogadro's number"# #=# #6.022xx10^23*mol^-1#

#"Number of moles"# #=# #"Mass"/"Molar mass"#

#=# #(27*g)/(54.00*g*mol^-1)=0.500*mol#

And thus #"Number of molecules"# #=# #6.022xx10^23*mol^-1#

#=# #3.011xx10^23# #OF_2# molecules..........

What is the oxdation number of oxygen in this molecule?

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