Question #7c802

Jan 5, 2017

Oxides that form neither an acid nor a base, in combination with water.

Explanation:

Acid oxides will react with water to ultimately give off ${H}^{+}$:
Sulphur trioxide $S {O}_{3}$ will form sulfuric acid:
$S {O}_{3} \left(g\right) + {H}_{2} O \left(l\right) \to {H}_{2} S {O}_{4}$ which will give off ${H}^{+}$

Basic oxides will accept ${H}^{+}$:
Calcium oxide $C a O$ will form a base:
$C a O \left(s\right) + {H}_{2} O \left(l\right) \to C a {\left(O H\right)}_{2}$
The $O {H}^{-}$ part combining with ${H}^{+}$ to form water.
Ferrous oxide $F e O$ will not combine with water, but it will accept ${H}^{+}$ from an acid:
$F e O + 2 {H}^{+} \to F {e}^{2 +} + {H}_{2} O$

Neutral oxides do neither. Examples are carbon monoxide ($C O$), nitrogen monoxide ($N O$), and of course water (${H}_{2} O$)