Question

Question #4c1f6

Answer 1

We know the expression for dispersive power `omega` as follows

`omega=(mu_F-mu_C)/(mu_D-1`

where

`mu_F->"refractive index in respect of F light"`

`mu_C->"refractive index in respect of C light"`

`mu_D->"refractive index in respect of D light"`

Given

`mu_F=1.805" "mu_C=1.790" "mu_D=`

So inserting the values we have

`omega=(mu_F-mu_C)/(mu_D-1`

`=>omega=(1.805-1.790)/(1.795-1)=0.015/0.795~~0.0188`