Question

Question #0297a

Answer 1

`"Molarity"="0.4 mol"*"L"^-1`

Explanation:

`"Molarity"="Moles of solute"/"Volume of solution"`

`=(2*"mol")/(0.500*"L")=0.4*"mol"*"L"^-1`.

So two questions for you:

(i) What is the concentration in `"g"*"L"^-1`?

(ii) What are (i) the `"pOH"`, and (ii) the `"pH"` of this solution?