How do you write #y = 5x- 32# in standard form?

1 Answer
EZ as pi
Jan 12, 2017

#5x -y = 32#

Explanation:

When dealing with equations of straight lines, there are 3 possible terms. The standard form is in the format:

#ax + by = c" "# where a, b, and c are all integers:

#y = 5x -32" "rarr 5x-32 = y#

Add 32 and subtract y on both sides:

#5x-y-32 +32 = y-y+32#

#5x -y = 32#

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