Question #e1aae

1 Answer
Jim G.
Mar 18, 2017

#f'(x)=xsec^2x+tanx#

Explanation:

differentiate using the #color(blue)"product rule"#

#"Given " f(x)=g(x)h(x)" then"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(f'(x)=g(x)h'(x)+h(x)g'(x))color(white)(2/2)|)))#

#"here "g(x)=xrArrg'(x)=1#

#"and " h(x)=tanxrArrh'(x)=sec^2x#

#rArrf'(x)=xsec^2x+tanx#

Related questions
See all questions in Differentiating Inverse Trigonometric Functions
Impact of this question
1178 views around the world
You can reuse this answer
Creative Commons License