Question

Question #5d180

Answer 1

Critical numbers are `0, pi, 2pi, (2pi)/3, (4pi)/3`

Explanation:

f'(x)= 2 sin x cos x +cos x

= sin x (2cos x +1)

For critical numbers f' (x)=0

sin x=0 ,gives x=0,`pi, 2pi`

2cos x +1=0, cos x= `-1/2` gives x= `(2pi)/3, (4pi)/3`