# Question #34902

##### 1 Answer

Here's what I got.

#### Explanation:

You can't really tell just by the information provided in the problem, but you *can* set up a conversion factor that can help you figure out how many grams of sodium carbonate you'd get in

In order to do that, let's assume that you know how many grams of sodium carbonate you have in the **grams** of sodium carbonate.

Now, your goal here is to *scale up* this **known composition** of the sample.

You know that

#"15 mL solution Na"_2"CO"_3 -> x" g Na"_2"CO"_3#

Now, you can go from *milliliters* to *liters* by using

#color(darkgreen)(ul(color(black)("1 L" = 10^3"mL")))#

You can now set up your conversion factors like this

#575 color(red)(cancel(color(black)("L solution"))) * (10^3color(red)(cancel(color(black)("mL solution"))))/(1color(red)(cancel(color(black)("L solution")))) * overbrace((x" g Na"_2"CO"_3)/(15color(red)(cancel(color(black)("mL solution")))))^(color(blue)("what you know"))#

# = (3.8 * x) * 10^4"g Na"_2"CO"_3#

You plug the value of