# If 19*mol of H_2(g) react with stoichiometric N_2(g), what molar quantity of ammonia results?

Jul 6, 2017

A bit under $13 \cdot m o l$ of ammonia..........

#### Explanation:

You have the stoichiometric equation........

${N}_{2} \left(g\right) + 3 {H}_{2} \left(g\right) \stackrel{\text{catalysis}}{\rightarrow} 2 N {H}_{3} \left(g\right)$

And clearly, if $19 \cdot m o l$ dihydrogen react completely (which is NOT an altogether probable outcome) then by the stoichiometry we get $\frac{19}{3} \times 2 \cdot m o l = 12.7 \cdot m o l$ with respect to ammonia, $N {H}_{3}$.......

What is the significance of this ammonia synthesis? Do you think that this reaction is widely performed?