If #19*mol# of #H_2(g)# react with stoichiometric #N_2(g)#, what molar quantity of ammonia results?

1 Answer
Jul 6, 2017

Answer:

A bit under #13*mol# of ammonia..........

Explanation:

You have the stoichiometric equation........

#N_2(g) + 3H_2(g) stackrel("catalysis")rarr2NH_3(g)#

And clearly, if #19*mol# dihydrogen react completely (which is NOT an altogether probable outcome) then by the stoichiometry we get #19/3xx2*mol=12.7*mol# with respect to ammonia, #NH_3#.......

What is the significance of this ammonia synthesis? Do you think that this reaction is widely performed?