Question

Question #932f1

Answer 1

It is a increasing function, Its range is `[0,oo)`

Explanation:

In the given interval `[0,pi/2]`, y, which is a product of two functions x and tan x, it would increase from 0 to `oo` because tan x increases from o to `oo` in this interval. This fact is corroborated by considering the behaviour of its first derivative.

Looking at the first derivative of y, y'= `x sec^2 x+tan x`, it is obvious that y' would always be positive in the given interval, which means that y would be a increasing function in that interval.