# You have a drug that has a concentration of 0.50*g*cm^-3. What volume of solution is delivered for a 2*g dose?

Jan 20, 2017

Then you would administer a $4 \cdot m L$ or $4 \cdot c {m}^{3}$ dose.

#### Explanation:

You have been given a concentration in $g \cdot c {m}^{-} 3$. The product, $\text{Volume "xx" concentration}$ gives the amount of solute in the drug.

This is clear dimensionally, when the units of volume and concentration cancel out to give an answer with the units of mass, i.e. $g$:

$0.50 \cdot g \cdot \cancel{c {m}^{-} 3} \times 4 \cdot \cancel{c {m}^{3}} = 2 \cdot g$.

Is this clear? As a chemist, I usually do not care too much about errors. You get a calculation or dilution wrong, and you simply say $\text{oops}$, and repeat the experiment (and hopefully conceal your mistake from your supervisor!). As a nurse or a medico, you get a dose wrong, and you might injure someone.