# Question 9a2b3

Jan 27, 2017

Here's what I get.

#### Explanation:

The "accepted value" is the value that chemists agree is correct.

SATP stands for $\textcolor{b l u e}{\text{Standard Ambient Temperature and Pressure}}$.

It is defined as a temperature of 25 °C (298.15 K) and a pressure of 1 bar.

The accepted value for the molar volume of an ideal gas at SATP is 24.79 L.

STP stands for $\textcolor{b l u e}{\text{Standard Temperature and Pressure}}$.

It is defined as a temperature of 0 °C (273.15 K) and a pressure of 1 bar.

The accepted value for the molar volume of an ideal gas at SATP is 22.41 L.

We can use the Ideal Gas Law to calculate these volumes.

$\textcolor{b l u e}{\overline{\underline{| \textcolor{w h i t e}{\frac{a}{a}} P V = n R T \textcolor{w h i t e}{\frac{a}{a}} |}}} \text{ }$

We can rearrange this formula to get

$V = \frac{n R T}{P}$

At SATP

V = (nRT)/P = (1 color(red)(cancel(color(black)("mol"))) × "0.083 14" color(red)(cancel(color(black)("bar")))·"L"color(red)(cancel(color(black)(" K"^"-1""mol"^"-1"))) × 298.15 color(red)(cancel(color(black)("K"))))/(1 color(red)(cancel(color(black)("bar")))) = "24.79 L"

At STP

V = (nRT)/P = (1 color(red)(cancel(color(black)("mol"))) × "0.083 14" color(red)(cancel(color(black)("bar")))·"L"color(red)(cancel(color(black)(" K"^"-1""mol"^"-1"))) × 273.15 color(red)(cancel(color(black)("K"))))/(1 color(red)(cancel(color(black)("bar")))) = "22.71 L"#