Question

At `"NTP"` what is the mass of a `0.448*L` volume of dinitrogen gas?

Answer 1

We take NTP as `293.15*K`, and `1*atm`.............

Explanation:

`n="Mass"/"Molar mass"=(PV)/(RT)`

Thus `"Mass"=(28.02*g*cancel(mol^-1)xx1*cancel(atm)xx0.448*cancelL)/(0.0821*cancel(L*atm*K^-1*mol^-1)xx293.15*cancelK)`

`~~0.5*g`