# How many "pascals" are in 3.05xx10^5*kPa?

The $\text{k}$ in $k P a$ $\equiv$ $\text{kilo, } {10}^{3}$
$3.05 \times {10}^{5} \cdot k P a = 3.05 \times {10}^{5} \times {10}^{3} P a = 3.05 \times {10}^{8} \cdot P a$