# Solve k/1+6?

$1 = \frac{k}{1} + 6 \implies k = - 5$
$1 = \frac{k}{1 + 6} \implies k = 7$

#### Explanation:

I'm going to answer this a couple of different ways using a couple of different assumptions.

First I'm going to assume there are no brackets, which gives us:

$1 = \frac{k}{1} + 6$

We know that anything divided by 1 is itself, so we can now write this as:

$1 = k + 6$

We can subtract 6 from both sides and we'll get:

$1 \textcolor{red}{- 6} = k + 6 \textcolor{red}{- 6}$

$- 5 = k$

Now I'm going to assume that there are brackets around the denominator on the right side, which gives us:

$1 = \frac{k}{1 + 6}$

First we simplify the denominator:

$1 = \frac{k}{7}$

At this point we can see that $k = 7$. But let's go ahead and finish solving it to prove it. Let's multiply both sides by 7:

$1 \textcolor{red}{\times 7} = \frac{k}{7} \textcolor{red}{\times 7}$

$7 = k$