# Question #507b8

Jan 26, 2017

This is $0.535$ mol of ${H}_{2}$ molecules
Since a mole of any objects is $6.02 \times {10}^{23}$ of those objects, we need only divide the given quantity by this value (known as Avogadro's constant).
$\frac{3.22 \times {10}^{23}}{6.02 \times {10}^{23}} = 0.535 m o l$
(The fact that the question refers to ${H}_{2}$ molecules does not affect the calculation at all.)