Question

Question #a03f5

Answer 1

`26.bar6" rad"cdot"s"^-2`

Explanation:

Expression connecting angular velocity `omega` and rpm is

`omega=2pif`
where `f` is revolution per second.

In the given problem
Initial angular velocity `omega_i=2pixx1200/60=20pi" rad"cdot"s"^-1`
Final angular velocity `omega_f=2pixx3000/60=100pi" rad"cdot"s"^-1`
Change in angular velocity `Delta omega=(100-20)pi=80pi" rad"cdot"s"^-1`
Average Rotational or Average Angular acceleration `baralpha-=(Deltaomega)/(Deltat)`
Therefore we have Average Angular acceleration `bar alpha=(80pi)/3`
`=26.bar6" rad"cdot"s"^-2`