Question #a03f5

1 Answer
Feb 14, 2017

Answer:

#26.bar6" rad"cdot"s"^-2#

Explanation:

Expression connecting angular velocity #omega # and rpm is

#omega=2pif#
where #f# is revolution per second.

In the given problem
Initial angular velocity #omega_i=2pixx1200/60=20pi" rad"cdot"s"^-1#
Final angular velocity #omega_f=2pixx3000/60=100pi" rad"cdot"s"^-1#
Change in angular velocity #Delta omega=(100-20)pi=80pi" rad"cdot"s"^-1#
Average Rotational or Average Angular acceleration #baralpha-=(Deltaomega)/(Deltat)#
Therefore we have Average Angular acceleration #bar alpha=(80pi)/3#
#=26.bar6" rad"cdot"s"^-2#