How many atoms in a #9.6*g# mass of sulfur?

1 Answer
anor277
Jan 28, 2017

#"Number of atoms"# #=# #"Mass"/"Molar mass"xx"Avogadro's number."#

Explanation:

#"Atoms of sulfur"# #=# #(9.60*g)/(32.06*g*mol^-1)xx6.022xx10^23*mol^-1#.

Because the units all cancel out, the answer is clearly a number, #~=2xx10^23# as required.

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