How many atoms in a $9.6*g$ mass of sulfur?

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Answer 1 · 2017-01-28T06:02:29

$"Number of atoms"$ $=$ $"Mass"/"Molar mass"xx"Avogadro's number."$

$"Atoms of sulfur"$ $=$ $(9.60*g)/(32.06*g*mol^-1)xx6.022xx10^23*mol^-1$ .

Because the units all cancel out, the answer is clearly a number, $~=2xx10^23$ as required.

How many atoms in a 9.6*g9.6*g mass of sulfur?