# What is the molarity of a solution of containing a mass of 250*g sodium chloride in a volume of 775*mL water?

Feb 1, 2017

We use the relationship,

$\text{Molarity}$ $=$ $\text{Moles of solute"/"Volume of solution (L)} \cong 6 \cdot m o l \cdot {L}^{-} 1$

#### Explanation:

And thus,

$\text{Molarity} = \frac{250.0 \cdot g}{58.44 \cdot g \cdot m o {l}^{-} 1} \times \frac{1}{775 \cdot m L \times {10}^{-} 3 \cdot L \cdot m {L}^{-} 1}$

=??mol*L^-1