Question

Between which two consecutive integers does the square root of `36` lie?

Answer 1

`sqrt(36) = 6` lies between consecutive odd integers `5` and `7`.

Explanation:

"The" square root of `36` is itself an integer, namely `6`, since `6^2 = 36`. So it does not lie between consecutive integers.

It does lie between consecutive odd integers `5` and `7`.

Note that `36` has another square root, namely `-6`, since `-6` satisfies:

`(-6)^2 = 36`