# Between which two consecutive integers does the square root of 36 lie?

Feb 1, 2017

$\sqrt{36} = 6$ lies between consecutive odd integers $5$ and $7$.

#### Explanation:

"The" square root of $36$ is itself an integer, namely $6$, since ${6}^{2} = 36$. So it does not lie between consecutive integers.

It does lie between consecutive odd integers $5$ and $7$.

Note that $36$ has another square root, namely $- 6$, since $- 6$ satisfies:

${\left(- 6\right)}^{2} = 36$