What is the mass of #4.70xx10^22# individual #"sulfur atoms"#?

1 Answer
Feb 10, 2017

Answer:

Approx. #2.5*g#

Explanation:

We know that #6.022xx10^23# individual sulfur atoms have a mass of #32.06*g#. How do we know this?

And thus we work out the product:

#32.06*g*mol^-1xx(4.70xx10^22cancel" sulfur atoms ")/(6.022xx10^23cancel" sulfur atoms "mol^-1)#

#=??*mol#

Note that as far as anyone knows, sulfur, as the yellow powder, is the #S_8# molecule. The size of the molecule probably explains its extreme insolubility in most solvents.