Question

What is the mass of `4.70xx10^22` individual `"sulfur atoms"`?

Answer 1

Approx. `2.5*g`

Explanation:

We know that `6.022xx10^23` individual sulfur atoms have a mass of `32.06*g`. How do we know this?

And thus we work out the product:

`32.06*g*mol^-1xx(4.70xx10^22cancel" sulfur atoms ")/(6.022xx10^23cancel" sulfur atoms "mol^-1)`

`=??*mol`

Note that as far as anyone knows, sulfur, as the yellow powder, is the `S_8` molecule. The size of the molecule probably explains its extreme insolubility in most solvents.