# Question #bd0ef

Feb 2, 2017

$z ' = 5 {s}^{4} - {s}^{2} / 5$

#### Explanation:

$z = {s}^{5} - {s}^{3} / 15$

Assuming you want the derivative of z wrt s, which seem highly likely, then you use the power rule:

${\left({x}^{n}\right)}^{p} r i m e = n {x}^{n - 1}$

here that means:

$z ' = 5 {s}^{4} - 3 {s}^{2} / 15$

$= 5 {s}^{4} - {s}^{2} / 5$