What mass is associated with a #17.8*mL# volume of aluminum metal?

Question

1426 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-17T07:31:27

This site reports that #rho_"Al"=2.7*g*cm^-3#

We know that #rho#, #"density"="unit mass"/"unit volume"#

And thus #"mass"="density"xx"volume"#

And thus, since #1*mL-=1*cm^3#, we take the product........

#"volume"xx"density"="mass"#

So #"mass"=rhoxx"volume"#

#=2.7*g*cancel(mL^-1)xx17.8*cancel(mL)=48*g#

The given product is dimensionally consistent. We want an answer in grams, and the product gives us an answer in grams.