# What mass is associated with a 17.8*mL volume of aluminum metal?

Jun 17, 2017

This site reports that ${\rho}_{\text{Al}} = 2.7 \cdot g \cdot c {m}^{-} 3$

#### Explanation:

We know that $\rho$, $\text{density"="unit mass"/"unit volume}$

And thus $\text{mass"="density"xx"volume}$

And thus, since $1 \cdot m L \equiv 1 \cdot c {m}^{3}$, we take the product........

$\text{volume"xx"density"="mass}$

So $\text{mass"=rhoxx"volume}$

$= 2.7 \cdot g \cdot \cancel{m {L}^{-} 1} \times 17.8 \cdot \cancel{m L} = 48 \cdot g$

The given product is dimensionally consistent. We want an answer in grams, and the product gives us an answer in grams.