Question #ed5b1

1 Answer
May 25, 2017

1/26+(5/26)i.126+(526)i.

Explanation:

Let, z=i/(5+i).z=i5+i.

rArr z=i/(5+i)xx(5-i)/(5-i),z=i5+i×5i5i,

=(5i-i^2)/(5^2-i^2),=5ii252i2,

=(5i-(-1))/(25-(-1)),=5i(1)25(1),

=(1+5i)/26,=1+5i26,

:. z=1/26+(5/26)i.