# What is the mass of a 1.26xx10^-4*mol quantity of acetic acid?

Feb 9, 2017

$\text{In acetic acid,}$ ${H}_{3} {\text{CCO}}_{2} H$?

#### Explanation:

Now, the basic equation is $\text{moles}$ $=$ $\text{mass"/"molar mass}$....and thus $\text{mass}$ $=$ $\text{moles}$ $\times$ $\text{molar mass}$.

So here,

$\text{mass}$ $=$ $1.26 \times {10}^{-} 4 \cdot \cancel{m o l} \times 60.05 \cdot g \cdot \cancel{m o {l}^{-} 1} = 7.60 \cdot m g$.

Certainly, this expression is dimensionally consistent. I wanted an answer with units of mass, and the calculation did in fact give such units.

Apr 2, 2018

The mass of $\text{CH"_3"COOH}$ is $\text{0.00757 g}$.

#### Explanation:

Multiply moles by molar mass.

The molar mass of acetic acid $\left(\text{CH"_3"COOH}\right)$ is $\text{60.052 g/mol}$.
https://www.ncbi.nlm.nih.gov/pccompound?term=%22acetic+acid%22

1.26xx10^(-4)color(red)cancel(color(black)("mol CH"_3"COOH"))xx(60.052"g CH"_3"COOH")/(1color(red)cancel(color(black)("mol CH"_3"COOH")))="0.00757 g CH"_3"COOH" (rounded to three significant figures)