What is the mass of a #1.26xx10^-4*mol# quantity of acetic acid?

2 Answers
Feb 9, 2017

Answer:

#"In acetic acid,"# #H_3"CCO"_2H#?

Explanation:

Now, the basic equation is #"moles"# #=# #"mass"/"molar mass"#....and thus #"mass"# #=# #"moles"# #xx# #"molar mass"#.

So here,

#"mass"# #=# #1.26xx10^-4*cancel(mol)xx60.05*g*cancel(mol^-1)=7.60*mg#.

Certainly, this expression is dimensionally consistent. I wanted an answer with units of mass, and the calculation did in fact give such units.

Apr 2, 2018

Answer:

The mass of #"CH"_3"COOH"# is #"0.00757 g"#.

Explanation:

Multiply moles by molar mass.

The molar mass of acetic acid #("CH"_3"COOH")# is #"60.052 g/mol"#.
https://www.ncbi.nlm.nih.gov/pccompound?term=%22acetic+acid%22

#1.26xx10^(-4)color(red)cancel(color(black)("mol CH"_3"COOH"))xx(60.052"g CH"_3"COOH")/(1color(red)cancel(color(black)("mol CH"_3"COOH")))="0.00757 g CH"_3"COOH"# (rounded to three significant figures)