From starting position #O# the bearing of current is #345^@# and that of direction of destination is #100^@#. So the angle between the direction of current and the direction of destination is #(360-345+100)^@=115^@#

Again the ship is to cover 700km in 20hr to reach at the destination

So its velocity along the direction of destination #OD# is

#V_d=700/20=35"km/h"#

The velocity of current along OC

is #V_c=5"km/h"#

Le the velocity of ship along OE will be #V_s# and this velocity makes an angle #alpha# with OD.

Considering cosine law for triangle ODE we can write

#V_s^2=V_c^2+V_d^2-2V_cV_dcos115#

#=>V_s^2=5^2+35^2-2*5*35cos115#

#V_s=37.4"km/h"#

Now applying sin law for triangle ODE we get

#V_d/sin115=5/sinalpha#

#=>37.4/sin115=5/sinalpha#

#=>sinalpha=5/37.4xxsin115~~0.12#

#=>alpha~~7^@#

So the bearing of the direction of the ship to be driven is #107^@#