Question #2be51

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SCooke
Feb 13, 2017

86.96 wt.% permanganate, 13.14 wt.% ammonium ions.

Explanation:

First, we must make sure that we have the correct molecular formula for ammonium permanganate. #NH_4MnO_4#.
Then we add up all of the element gram-masses to find the total gram-molecular weight of the compound. Then we take the gram-mass of the permanganate ion and divide it by the total mass to get the relative percentage composition.

#NH_4# = 18 #MnO_4# = 119 #NH_4MnO_4# = 137

#NH_4#/#NH_4MnO_4# = 18/137 = 0.1314 = 13.14 wt.%

#MnO_4# /#NH_4MnO_4# = 119/137 = 0.8686 = 86.86 wt.%

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