# Question #2be51

Feb 13, 2017

86.96 wt.% permanganate, 13.14 wt.% ammonium ions.

#### Explanation:

First, we must make sure that we have the correct molecular formula for ammonium permanganate. $N {H}_{4} M n {O}_{4}$.
Then we add up all of the element gram-masses to find the total gram-molecular weight of the compound. Then we take the gram-mass of the permanganate ion and divide it by the total mass to get the relative percentage composition.

$N {H}_{4}$ = 18 $M n {O}_{4}$ = 119 $N {H}_{4} M n {O}_{4}$ = 137

$N {H}_{4}$/$N {H}_{4} M n {O}_{4}$ = 18/137 = 0.1314 = 13.14 wt.%

$M n {O}_{4}$ /$N {H}_{4} M n {O}_{4}$ = 119/137 = 0.8686 = 86.86 wt.%