A #73*mL# volume of gas enclosed in a piston at a pressure of #100*kPa#, and a temperature of #0# #""^@C# was heated to a temperature of #80# #""^@C# and the new volume occupied was #4530*mL#. What is the new pressure that the gas exerts?

1 Answer
Aug 23, 2017

Answer:

Well for a given molar quantity of gas, #(P_1V_1)/T_1=(P_2V_2)/T_2#

Explanation:

Temperature must be quoted on the #"Kelvin scale"#, and so...

#P_2=(P_1V_1)/T_1xxT_2/V_2#, which will certainly give us an answer with the required units of pressure. Why so?

And thus...........

#P_2=(100*kPaxx73.0*mL)/(273.15*K)xx(353.15*K)/(4530*mL)#

#~=2*kPa#

The pressure change is marked because we increase the volume GREATLY........i.e. more than 50 times the original volume, whereas the temperature is increased only marginally.