Question #f8fe8
1 Answer
Jun 15, 2017
Explanation:
Since we're differentiating with respect to
The function in question is
So, with respect to
#d/dxcos^2(a+y)=0#
Since we're differentiating with respect to
The function in question is
So, with respect to
#d/dxcos^2(a+y)=0#