What is the mass associated with #4.70xx10^22# #"sulfur atoms"#?

1 Answer
Feb 15, 2017

#"Approx. 2.5 g"#

Explanation:

We know that #N_A,"Avogadro's number,"# #6.022xx10^23# of #"sulfur atoms"# have a mass of #32.06*g# precisely. How do we know this?

And thus we can multiply the number quotient by the molar mass to give:

#(4.70xx10^22*"sulfur atoms")/(6.022xx10^23*mol^-1*"sulfur atoms")xx32.06*g*mol^-1-=#

#??g#