# What is the mass associated with 4.70xx10^22 "sulfur atoms"?

Feb 15, 2017

$\text{Approx. 2.5 g}$

#### Explanation:

We know that ${N}_{A} , \text{Avogadro's number,}$ $6.022 \times {10}^{23}$ of $\text{sulfur atoms}$ have a mass of $32.06 \cdot g$ precisely. How do we know this?

And thus we can multiply the number quotient by the molar mass to give:

$\left(4.70 \times {10}^{22} \cdot \text{sulfur atoms")/(6.022xx10^23*mol^-1*"sulfur atoms}\right) \times 32.06 \cdot g \cdot m o {l}^{-} 1 \equiv$

??g