Question

Given the reaction... `" "` `3(NH_4)_2PtCl_6(s) + Delta rarr 3Pt(s) + 2NH_4Cl(s) + 2N_2(g) +16HCl(g)` `" "` Can you address the following question?

How much platinum metal can be produced from a `15*mol` quantity of `"ammonium hexachloroplatinate(IV)"` salt?

Answer 1

`"Moles of platinate"` `-=` `"moles of platinum metal"`

Clearly, 15 moles of platinum metal can produced from the `Pt(IV)` salt.

Explanation:

You have the stoichiometric reaction, and, CLEARLY, there is 1:1 molar equivalence between the platinum salt and platinum metal:

`3(NH_4)_2PtCl_6(s) + Delta rarr 3Pt(s) + 2NH_4Cl(s) + 2N_2(g) +16HCl(g)`

Each mole of platinate gives a mole of platinum metal. As written, this is a redox reaction. What species has been reduced, and what species have been oxidized?