# Given the reaction... " " 3(NH_4)_2PtCl_6(s) + Delta rarr 3Pt(s) + 2NH_4Cl(s) + 2N_2(g) +16HCl(g) " " Can you address the following question?

## How much platinum metal can be produced from a $15 \cdot m o l$ quantity of $\text{ammonium hexachloroplatinate(IV)}$ salt?

Feb 16, 2017

$\text{Moles of platinate}$ $\equiv$ $\text{moles of platinum metal}$

Clearly, 15 moles of platinum metal can produced from the $P t \left(I V\right)$ salt.

#### Explanation:

You have the stoichiometric reaction, and, CLEARLY, there is 1:1 molar equivalence between the platinum salt and platinum metal:

$3 {\left(N {H}_{4}\right)}_{2} P t C {l}_{6} \left(s\right) + \Delta \rightarrow 3 P t \left(s\right) + 2 N {H}_{4} C l \left(s\right) + 2 {N}_{2} \left(g\right) + 16 H C l \left(g\right)$

Each mole of platinate gives a mole of platinum metal. As written, this is a redox reaction. What species has been reduced, and what species have been oxidized?