Given the reaction... #" "# #3(NH_4)_2PtCl_6(s) + Delta rarr 3Pt(s) + 2NH_4Cl(s) + 2N_2(g) +16HCl(g)# #" "# Can you address the following question?

How much platinum metal can be produced from a #15*mol# quantity of #"ammonium hexachloroplatinate(IV)"# salt?

1 Answer
Feb 16, 2017

Answer:

#"Moles of platinate"# #-=# #"moles of platinum metal"#

Clearly, 15 moles of platinum metal can produced from the #Pt(IV)# salt.

Explanation:

You have the stoichiometric reaction, and, CLEARLY, there is 1:1 molar equivalence between the platinum salt and platinum metal:

#3(NH_4)_2PtCl_6(s) + Delta rarr 3Pt(s) + 2NH_4Cl(s) + 2N_2(g) +16HCl(g)#

Each mole of platinate gives a mole of platinum metal. As written, this is a redox reaction. What species has been reduced, and what species have been oxidized?