Question #02601

Feb 17, 2017

The normality of the acid is 0.20 eq/L.

Explanation:

The equation is

$\textcolor{w h i t e}{m m m m m m} \text{M(OH)"_2 + "Acid" → "salt + water}$
$\text{Amt/meq:} \textcolor{w h i t e}{m m l} 20 \textcolor{w h i t e}{m m m l l} 20$

An equivalent is the amount of acid or base that delivers one mole of $\text{H"^"+}$ or $\text{OH"^"-}$ ions.

Thus, 10 mmol of ${\text{M(OH)}}_{2}$ represents 20 meq of the base.

It reacts with 20 meq of the acid.

$\text{Normality" = "20 meq"/"100 mL" = "0.20 meq/mL" = "0.20 eq/L}$