Question #59194
2 Answers
Feb 4, 2018
As explained
Explanation:
Since triangles ABC & AQR are similar,
Also
But AQ = AB * 1.5 = 5 * 1.5 = 7.5 cm#
From the diagram,
BC = (CD) / sin 60 = 3 / (sqrt3/2) = 2 sqrt3 = 3.4641#
QR = (BC) * 1.5 = 3.4641 * 1.5 = 5.196 cm#
Now we know two sides AQ, QR and included angle
Now we can construct
Feb 4, 2018
drawn
Steps for construction
- Line segments of length 5cm and 3cm are drawn with the help of a ruler.
- A line segment
AX of length> 8cm is also drawn similarly. - Line segment
AB is then cut off from AX with the help of a compass. /_ABK=60^@ is drawn with the help of a ruler and a compass.- With the help of a ruler and a compass a perpendicular
AN onAB atA is drawn and an interceptAP=3cm is cut off with the help of a compass. PO is drawn parallel toAB with the help of a compass and a ruler.PO intersectsBK atC .A and C are joined . TheDeltaABC is the required triangle having altitudeCD=3cm .AB is bisected atE with the help of a compass and a ruler.- Line segment
BQ=BE is cut off from extended part ofAB to makeAQ=1.5xxAB . /_AQL=60^@ is drawn to get getQL"||"BC . This QL intersects extendedAC atR .- Now
DeltaAQR is the similar toDeltaABC having1.5 times of the corresponding sides ofDeltaABC .