# Question #0bcbf

Time taken to cover $100 m$ with initial horizontal velocity of $500 m {s}^{-} 1$
$t = \text{Distance"/"Velocity} = \frac{100}{500} = 0.2 s$
The bullet falls freely under gravity in vertical direction with initial velocity of $0$. Vertical defection in vertical in $0.2 s$ is found using the kinematic equation
$d = u t + \frac{1}{2} g {t}^{2}$
$\implies d = 0 \times 0.2 + \frac{1}{2} \times 9.81 \times {\left(0.2\right)}^{2} \approx 0.196 m$
$\implies d = \approx 0.196 m$