Question

Question #e73e6

Answer 1

x= -5

Explanation:

Critical numbers are those values of x for which f'(x)=0 or f'(x) does not exist.

In the present case `f'(x)= 6/7 (x+5)^(-1/7)`

= `6/(7(x+5)^(1/7)`

For x= -5, f'(x) does not exist, hence x=-5 is a critical point