# Question e73e6

Feb 23, 2017

x= -5

#### Explanation:

Critical numbers are those values of x for which f'(x)=0 or f'(x) does not exist.

In the present case $f ' \left(x\right) = \frac{6}{7} {\left(x + 5\right)}^{- \frac{1}{7}}$

= 6/(7(x+5)^(1/7)#

For x= -5, f'(x) does not exist, hence x=-5 is a critical point