When octane is completely combusted, what is the whole number ratio between the dioxygen reactant, and the product hydrogens?

1 Answer
anor277
Feb 22, 2017

Well, clearly it's 25:18.

Explanation:

You have the balanced chemical equation:

C_8H_18(l) + 25/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)

And the stoichiometry precisely specifies that "25 equiv" of oxygen gas are required for complete combustion of "2 equiv" of "octane", to give "16 equiv" of "carbon dioxide" and "18 equiv" of "water."

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