Question

Question #732ab

Answer 1

`y’ = 4/sqrt(x^2 - 2)`

Explanation:

d /(dx) (cos^-1 x) = -1/sqrt(1-x^2)#

`y = cos ^-1 (2/x^2)`
`:. y’ = (-1/(sqrt(1-(2/x^2))) * (-4/x))`

`y’ = (4/cancel(x))(cancel(x )/ (sqrt(x^2 - 2)))`

`y’ = 4 / sqrt(x^2 - 2)`